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10/22/20: In this short episode for my Algebra II class, I will be explaining how I was able to solve for parts a-d of exploration question number 22. My answers go as follows:
A) y = (ce-af)/(bc-ad)
B) x = (de-bf)/(ad-bc)
C) y = (-ce+af)/(ad-bc), x = (de-bf)/(ad-bc)
D) The solutions were the same; (-4, 4.5). Using the following variables: a=2, b=4, c=6, d=8, e=10, and f=12, both of my solutions had an x value of -4 and a y value of 4.5.
10/22/20: In this short episode for my Algebra II class, I will be explaining how I was able to solve for parts a-d of exploration question number 22. My answers go as follows:
A) y = (ce-af)/(bc-ad)
B) x = (de-bf)/(ad-bc)
C) y = (-ce+af)/(ad-bc), x = (de-bf)/(ad-bc)
D) The solutions were the same; (-4, 4.5). Using the following variables: a=2, b=4, c=6, d=8, e=10, and f=12, both of my solutions had an x value of -4 and a y value of 4.5.