Using the u-substitution Technique with an Indefinite Integral (4-R p301 #59) A basic example of how to integrate something that looks like a product, where one factor has something in common with the derivative of the other factor.

 Basic Use of the First Fundamental Theorem (4-R p 310 #41) Here we use the First Fundamental Theorem of Calculus to evaluate a definite integral, and we will check our work with a TI-84 calculator,

 Riemann Sums to Estimate an Integral (4-R p 309 #25) Here we use left and right Riemann sums to get the upeer and lower bounds on an integral. We can then use the TI-84 to check our work.

Mean Value Theorem for Integrals with the TI-84 (4-5#85) Estimating Average Sales with t he TI-84 and the Mean Value Theorem for Integrals (4-5#85)

  This appears to be a counter example that would disprove the Alternating Series Remainder Theorem.... 

 A u-Substitution Using the Same U Formula Two Ways (4.5 p. 306 #57)

 Using the TI-84 to Explore Some Accumulator Functions (4-5 p 307 #87) The Calculator can compute the area between the x-axis and the blue function using brute force. We notice some relationships between them and spot points of inflection and extrema. 

A Definite Integral with u-Substitution (4-5 p 305 #61).   This one has a surprising result!

 4-5 p 307 #81  Some Complicated Integrals That Are Easier than they Appear! 4-5 p 307 #81  Some Complicated Integrals That Are Easier than they Appear!  U-substitution to the rescue!

Using the Chain Rule with an Accumulator Function (4-4 p294 #83, 85)  If the derivative of the upper limit has a derivative more complicated than 1, then your better use the chain rule!