This is not the kind of story that wraps up neatly with a bow. Rebecca Fraser’s story is raw, messy, and unfinished because healing after deep betrayal, family fracture, and years of abusive relationships with narcissists is never clean or simple. It’s the kind of survival story that digs into the parts most people don’t want to talk about, the shame, the loneliness, the repeated heartbreak, and the unbearable weight of carrying trauma in your body for years.In this episode, Rebecca shares her lived experience of growing up in a home torn apart by infidelity and addiction, being cast as the “problem child,” shuffled into foster care as a teenager, and entering a series of romantic relationships that only deepened her wounds. Alongside this emotional pain, she has been fighting a long battle with Lyme disease, a battle she believes was intensified by the unrelenting stress and trauma she endured.We explore the nervous system scars left by betrayal trauma, the painful roles children are assigned within dysfunctional families, and the long-term impact of being repeatedly gaslit, invalidated, and silenced not just by partners, but by family and community. Rebecca speaks openly about the heartbreak of losing friendships, the feeling of being “too much” for others, and the internal struggle of not trusting herself to choose safe people anymore. Don’t ever be alone in your journey and make sure you come and join my private Facebook community, No Visible Bruises where you can connect with other survivors of narcissistic abuse, domestic abuse and coercive control:https://www.facebook.com/groups/novisiblebruises.

Disclaimer:

The views and opinions shared in this podcast are those of the individuals involved and are intended for informational and educational purposes only. They do not substitute professional or medical advice. If you’ve been affected by anything discussed in today’s episode, please consider reaching out to a qualified healthcare provider or mental health professional for support. You’re not alone, and help is always available.